Steve Jones

My background is I have been working with computers since I was about 12. My first "career" job in this industry was with network administration where I became the local DBA by default. I have also spent lots of time administering Netware and NT networks, developing software, managing smaller IT groups, making lots of coffee, ordering pizza for late nights, etc., etc.

I currently am the editor of SQL Server Central and an advocate/architect at Redgate Software. I am also the President of SQL Saturday, maintain the T-SQL Tuesday monthly party, and remember our colleagues at sqlmemorial.org.

You can find out more about me on my blog (www.voiceofthedba.com) or LinkedIn (www.linkedin.com/in/way0utwest)
  • Interests: yoga, reading, biking, snowboarding, volleyball

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SQLServerCentral Article

Performance Tuning Stored Procedures

Stored procedures are a great way to encapsulate code and reuse it in many places in your application. But when you have a performance issue, how do you know which part of the stored procedure is giving you problems? Steve Jones takes a look at a few techniques for diving into stored procedures and identifying problem areas.

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2006-07-20

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Fun with JSON II

By Steve Jones - SSC Editor

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Changing Data Types

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Changing Data Types

Answering Questions On Dropped Columns

By Cláudio Silva

Comments posted to this topic are about the item Answering Questions On Dropped Columns

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Question of the Day

Fun with JSON II

I have some data in a table: 

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned? 
SELECT t1.[key] AS row,
       t2.*
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t1
    CROSS APPLY OPENJSON(t1.value) t2;

See possible answers