Articles

External Article

Database source control workshop, Cambridge UK

Redgate is hosting a 1 day public workshop on April 22, 2015. This workshop will teach you how to put a database in source control, deploy a database from source control, and monitor database changes across development, testing, and production environments.

2015-03-24

7,650 reads

External Article

Integrating Database Lifecycle Management into Microsoft's Application Delivery Process

In order to automate the delivery of an application together with its database, you probably just need the extra database tools that allow you to continue with your current source control system and release management system by integrating the database into it. If you're using the Microsoft stack, then Redgate's tools can help with some of the difficult database parts of the process, as Jason Crease demonstrates.

2015-03-24

8,081 reads

Technical Article

SQL Saturday #364 - Boston, MA

SQL Saturday is coming to Boston on April 18th 2015. Join us for a free day of SQL Server training and networking, and listen to great speakers like Grant Fritchey, Brent Ozar, and Andy Leonard. Register while space is available.

2015-03-19

7,512 reads

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Forums

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Question of the Day

The Tightly Linked View

I try to run this code on SQL Server 2022. All the objects exist in the database.

CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
       cl.CityName,
       o.OrderID,
       o.Customer,
       o.OrderDate,
       o.CustomerID,
       o.cityId
 FROM dbo.CityList AS cl
 INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
    @OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
    DECLARE @city VARCHAR(50);
    SELECT @city = os.CityName
    FROM dbo.OrderShipping AS os
    WHERE os.OrderID = @OrderID;
    RETURN @city;
END;
go
What is the result?

See possible answers