2008-12-23
632 reads
2008-12-23
632 reads
2008-12-23
626 reads
The need to run a stored procedure or SQL Agent Job when SQL Server or SQL Agent starts is a common requirement in the world of SQL Server administration. This article gives an overview of the ways to execute SQL stored procedures or SQL Agent jobs on startup.
2008-12-23
2,546 reads
This is the final article in a series on how to perform data visualisation with SQL Server 2008
2008-12-23
2,302 reads
This article introduces the PerlDTS project that provides a Perl distribution to access and execute MS SQL Server 8 DTS packages.
2008-12-22
3,026 reads
This article is part one of a two part series on how to perform data visualisation with SQL Server 2008
2008-12-22
3,010 reads
Do computers help us learn quicker? Do we need to in today's wired world? Steve Jones talks a little about learning in today's editorial
2008-12-22
1,003 reads
Do computers help us learn quicker? Do we need to in today's wired world? Steve Jones talks a little about learning in today's editorial
2008-12-22
741 reads
Do computers help us learn quicker? Do we need to in today's wired world? Steve Jones talks a little about learning in today's editorial
2008-12-22
724 reads
Learn the basics to create a SQL inner join and SQL outer join. Get examples on how to use them for a customized result set querying more than one table.
2008-12-22
5,822 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers