DevOps

SQLServerCentral Article

Manage Elastic jobs in Azure using Azure Elastic Jobs Manager

  • Article

Microsoft Azure offers Azure Elastic Job agent as a managed service, enabling efficient scheduling of T-SQL workloads on Azure SQL Databases. Learn how to configure the service in this article.

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2024-06-07 (first published: )

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External Article

How to Automate Cross-Platform Database Development

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In order to focus on their primary task of developing databases, the development team need to automate as many as possible of the routine tasks that are essential for database delivery, such as testing, scripting, version control, documentation, code review, reporting and so on. This article gives some advice on how to do it, faced with the added challenge of needing to use several different relational databases.

2023-04-28

SQLServerCentral Article

A Version Control Strategy for Branch-based Database Development

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The migration to a different VCS should not be underestimated, as there is a lot more involved than just switching tools, and that’s what Tonie Huizer covers in this article.
First, the team needed to migrate the monolithic repos over to Git, second the team needed to make sure we had a branching strategy and workflow in place.
It involved a big process change for the team as well, but this switch is mandatory to make full use of branch-based database development.

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2023-02-08

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Question of the Day

The Read Committed Snapshot Isolation behaviour

I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON: 

use master;
go

alter database AdventureWorks set read_committed_snapshot on with no_wait;
go
Then, from Session 1, I execute the following code: 
--Session 1
use AdventureWorks;
go

create table ##t1 (id int, f1 varchar(10));
go

insert into ##t1 values (1, 'A');
From another session, called Session 2, I open a transaction and execute the following update: 
--Session 2
use AdventureWorks;
go

begin tran;
update ##t1 
set f1 = 'B'
where id = 1;
Now, going back to Session 1, what happens if I execute this statement? 
--Session 1
select f1
from ##t1
where id = 1;
 

See possible answers