2012-08-24 (first published: 2007-09-29)
1,684 reads
2012-08-24 (first published: 2007-09-29)
1,684 reads
2012-08-23 (first published: 2008-06-05)
1,699 reads
2012-08-22 (first published: 2008-03-24)
1,887 reads
Tool to automatically query combinations of columns in your table to determine candidate for unique key.
2012-08-21 (first published: 2008-01-28)
2,849 reads
Displays the names of all of the SQL databases on a SQL Server instance, their data and transaction log files, their owner, and their physical locations.
2012-08-20 (first published: 2012-07-27)
1,582 reads
Remove the first replications of a specified char in a word. It does not work well with text that contains blank spaces in the middle.
2012-08-16 (first published: 2012-08-02)
949 reads
Generate a per-schema, per-procedure ordered list of all stored procedures for the current database, together with their parameters, datatypes and nullability.
2012-08-14 (first published: 2012-08-08)
2,235 reads
This helps to get list of all objects in a particular schemas.
2012-08-13 (first published: 2012-08-08)
1,145 reads
2012-08-13 (first published: 2012-07-31)
1,782 reads
Index Maintenance procedure with HTML Reporting capabilities. Please refer to attached script for detailed information.
2012-08-09 (first published: 2012-07-26)
1,644 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers