2016-08-11 (first published: 2015-06-12)
3,664 reads
2016-08-11 (first published: 2015-06-12)
3,664 reads
2016-08-10 (first published: 2015-05-05)
5,496 reads
This iTVF will produce a calendar table that can be used for complex date manipulation; quickly and effeciently
2016-08-08 (first published: 2014-12-29)
8,564 reads
Generates # of dates in before/after current year.
No more hardcoded date ranges.
2016-08-08 (first published: 2016-07-28)
613 reads
Identify the current statement and its line number within a running batch. Includes a link to the execution plan, if available.
2016-08-08 (first published: 2015-03-03)
5,447 reads
This script will detect and display a quick summary of your SQL Server installation.
2016-08-03 (first published: 2015-01-29)
9,527 reads
This script reports jobs which are running when another job is also running. This could be a reason for performance degradations.
2016-07-29 (first published: 2014-06-21)
2,665 reads
A script we use in our company, that rebuilds online=on by default, but takes care of special exceptions.
2016-07-28 (first published: 2014-06-06)
2,369 reads
Based upon todays date as suffix and chosen string as prefix, select data from predefined table into dynamically named new table. Script is properly error handled with most common errors
2016-07-27 (first published: 2015-05-04)
2,586 reads
2016-07-26 (first published: 2014-11-20)
2,255 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
Telp Cs: 08218200233 Jl. Merdeka No.39, Proklamasi, Kec. Siantar Bar., Kota Pematang Siantar, Sumatera...
Telp Cs: 08218200233 Jl. Asia, Simpang, Jl. Bakaran Batu No.1 C, Sei Rengas II,...
Telp Cs: 08218200233 Wisma Asia, Jl. Letjen S. Parman No.Kav. 79, RT.4/RW.9, Kota Bambu...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers