2009-03-23 (first published: 2009-02-17)
991 reads
2009-03-23 (first published: 2009-02-17)
991 reads
2009-03-19 (first published: 2009-02-17)
1,462 reads
This code will drop all stored procedures made with splog. With minor modification it will also drop all functions and sp not made with splog.
2009-03-13 (first published: 2009-02-12)
1,048 reads
2009-03-11 (first published: 2009-02-13)
1,793 reads
Dynamically creates a VB.NET class from parameters in a SQL Stored procedure.
2009-03-09 (first published: 2009-02-16)
1,070 reads
This script uses the system backup history to run a differential backup and place it in the directory of the last full backup.
2009-03-06 (first published: 2009-02-12)
651 reads
2009-03-04 (first published: 2009-02-16)
1,286 reads
This function will return the first, second, third, fourth or last day of a given month.
2009-03-03 (first published: 2009-02-10)
1,224 reads
Find And Replace any string, in the entire table with this function. Parameterized for easy use.
2009-02-26 (first published: 2009-02-09)
907 reads
The default trace keeps the last 20 meg of info, and a max of 5 files...This loads all 5 files into a table so it can be reviewed.
2009-02-25 (first published: 2009-02-07)
1,278 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers