How to get all MSSQL database columns names, data types and length
know all database columns names and data types and lenght with the minimum effort
2010-12-09 (first published: 2010-12-06)
3,039 reads
Scripts
Windows Group Membership Checker
A script to reveal which logins have access to your sql server via windows groups.
2010-12-09 (first published: 2010-08-26)
2,431 reads
2010-12-08 (first published: 2010-12-03)
1,984 reads
2010-12-07 (first published: 2010-11-30)
2,191 reads
2010-12-06 (first published: 2010-11-22)
2,618 reads
2010-12-03 (first published: 2010-11-22)
1,711 reads
Average Page Life Expectancy
A useful script that I wrote that will sample the DMV sys.dm_os_performance_counters table to provide an average PLE captured in (1) minute intervals.
2010-12-01 (first published: 2010-11-16)
1,684 reads
SQL Function to Split Comma Separated Values and Insert into Table
SQL Function to Split Comma Separated Values and Insert into Table
2010-11-30 (first published: 2010-11-07)
4,222 reads
2010-11-26 (first published: 2010-11-04)
582 reads
2010-11-18 (first published: 2009-07-20)
2,950 reads
Blogs
KDA: Echoes of Deception - Case 6
By Zikato
A cryptic message, a book cipher hidden in art provenance records, and a trail...
Capturing My Own Metrics: #SQLNewBlogger
By Steve Jones
A customer was trying to compare two tables and capture a state as a...
Red Flags in Your Query (T-SQL Tuesday #200)
By Zikato
When I'm looking at a query, I bet it's bad if I see... a...
Forums
BIT_COUNT II
Comments posted to this topic are about the item BIT_COUNT II
I Can't Make You Learn
Comments posted to this topic are about the item I Can't Make You Learn
Why Your SQL Permissions Disappeared
Comments posted to this topic are about the item Why Your SQL Permissions Disappeared
Question of the Day
BIT_COUNT II
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers