2010-12-23
3,458 reads
2010-12-23
3,458 reads
I have added 2 functions here, one for email validation and another to split the string by specified separator by user.
2010-12-23 (first published: 2010-12-11)
1,695 reads
A Stored Procedure for your tools database. It lists uncompressed tables and indexes and also generates the SQL to compress them.
2010-12-22 (first published: 2009-08-27)
950 reads
Report unusual conditions that may be filling up your transaction log.
2010-12-22
534 reads
A generic character padding function. Useful for situations where you need fixed width formatting e.g. email reports.
2010-12-20 (first published: 2010-03-31)
2,308 reads
Script to get a list of publications an article is in
2010-12-17 (first published: 2010-12-08)
3,786 reads
This script reveals the state of your indexes. It breaks down the indexes where they are partitioned, matching the index to it’s partition and filegroup.
2010-12-16 (first published: 2010-04-22)
7,574 reads
This function evaluates the statement like '4+5*6-3' and returns the numeric value.It is just like Eval funcction in javascript.
2010-12-15 (first published: 2010-12-08)
1,061 reads
2010-12-14 (first published: 2010-11-30)
3,851 reads
Script to grant exec permission to all sps in a db
2010-12-13 (first published: 2010-12-09)
1,733 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
By ChrisJenkins
Have you been thinking about migrating your reporting to Microsoft Fabric or Snowflake but...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
WA:08218154393 Jl. Wolter Monginsidi No.54, RT.2/RW.4, Petogogan, Kec. Kby. Baru, Kota Jakarta Selatan, Daerah...
WA:08218154393 Menara BCA, Grand Indonesia, Jl. M.H. Thamrin No.1, RT.1/RW.5, Menteng, Kec. Menteng, Kota...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers