2012-01-30 (first published: 2011-12-23)
876 reads
2012-01-30 (first published: 2011-12-23)
876 reads
Use this script to calculate MAX memory setting on a dedicated SQL server.
2012-01-27 (first published: 2011-12-14)
3,472 reads
2012-01-25 (first published: 2011-11-09)
1,272 reads
2012-01-25 (first published: 2011-12-15)
1,185 reads
find and replace text in a text file using tsql
2012-01-23 (first published: 2011-12-16)
3,107 reads
2012-01-20 (first published: 2011-12-16)
1,012 reads
will create jobs script for backup or DR purposes to install on another server.
2012-01-18 (first published: 2011-12-15)
2,162 reads
This script will backup your files that have changed only. old files will not be copied just newer ones.
2012-01-17 (first published: 2011-09-20)
713 reads
Do you know what happens if a holiday falls on a weekend? This script will help you.
2012-01-16 (first published: 2011-12-14)
3,055 reads
This select will show the last sql statement for every open session plus many helpfull information.
2012-01-13 (first published: 2008-03-04)
4,195 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers