External Article

Azure SQL Database - Azure AD Authentication

One of the challenges when considering migrating your on-premises SQL Server databases to Azure SQL Database is its lack of support for Active Directory-integrated authentication. With the advent of Azure SQL Database V12, the authentication capabilities have been expanded, allowing for more flexibility that leverages Azure Active Directory. In this article, Marcin Policht provides an overview of this functionality.

External Article

Taking Pictures from HTML

Sometimes a request from a user who doesn't appreciate the limitations of the technology can jolt you into discovering that an application feature that was, until recently, difficult to achieve is suddenly relatively easy. Dino was asked to allow the user to take photographs and associate them with an item of work. After he'd recovered from the shock, he decided that it was achievable, and now describes how he went on and did it.

Blogs

Learn about Modern Microsoft Apps in San Diego

By

I wrote about learning today for the editorial: I Can’t Make You Learn. I...

How To Deploy Fabric SQL and Azure SQL Databases with Azure DevOps

By

Fabric has CI/CD built in, but if you've tried to use it for database...

A New Word: Attriage

By

attriage – n. the state of having lost all control over how you feel...

Read the latest Blogs

Forums

Getting results from a Procedure to join to a query

By bswhipp

I have a need to execute a stored procedure and return the results to...

Upgrade 2016 Standard to 2022 Express

By pdanes

Title pretty much says it all - can this be done? I've tried several...

BIT_COUNT II

By Steve Jones - SSC Editor

Comments posted to this topic are about the item BIT_COUNT II

Visit the forum

Question of the Day

BIT_COUNT II

In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:

UserID  UserPermissions
15
23
37
4       NULL
What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount
from dbo.UserPermission
where UserID = 4;

See possible answers