DevOps and “Shift Left” for Databases
The easiest way of explaining how a DevOps approach to database deployment can dramatically speed up the process is to use the term ‘shift-left’. By performing, or at least...
The easiest way of explaining how a DevOps approach to database deployment can dramatically speed up the process is to use the term ‘shift-left’. By performing, or at least...
In an effort to make leading wildcard searches sargable, Aaron Bertrand plays around with a trigram-type implementation in SQL Server.
Machine learning and AI are becoming more and more prevalent, which Steve Jones thinks is good.
In this article, you will learn how to troubleshoot error when you try to launch the main Dashboard Report.
This week Steve looks at the challenges of security for medical data.
SQL Server Encryption is an essential part of what is required for protecting data. Column-level encryption can be a very effective way of doing this. In the first in a series of articles on the theme of SQL Server Encryption, Robert Sheldon once more makes it all seem easy.
This is the last week for a discounted registration to SQL Bits 2017. The price goes up after Mar 4, so register today.
Here a quick script showing how to get all the Active Directory users in a AD group.
A RAG pipeline that answers questions in the demo is not the same thing...
By Steve Jones
“A multitude of bad ideas is necessary for one good idea” – from Excellent...
Yesterday I gave a talk for MSSQLTips called “Building a DBA Agent for Your...
I've got a web application for my side business. I've added a SQL Server...
Comments posted to this topic are about the item Looking for New Blood
Comments posted to this topic are about the item Server-Level Row Counts for Tables...
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers