How to create a CLR assembly on a remote server with limited permissions
How to create external_access CLR assembly on remote MS SQL server, when trustworthy option is forbidden, and only SQL login is available
How to create external_access CLR assembly on remote MS SQL server, when trustworthy option is forbidden, and only SQL login is available
Steve rounds up the patch news for SQL Server this week along with a look forward to the next version of the platform.
The answers to questions from our webinar on Sandbox development.
This challenge is to generate an HTML calendar based on the data stored in a table.
Continuing from Part 1 , our Migration Checklist continues: Step 5: Update statistics It is always a good idea to update the statistics of the database that you have just installed or migrated
Come get a free day of SQL Server training in Birmingham on Jul 30, 2011.
Get three days of training in Raleigh, NC on Aug 18-20. There are free and paid options that you can read more about.
In the sixth part of his series on monitoring your SQL Server, David Bird looks at process locks.
Be reasonable. That's how Steve Jones thinks managers ought to behave towards their employees.
See a short and dirty example how to use temporary table in user defined function (UDF).
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
WhatsApp: 0817839777 Jl. Jend. Ahmad Yani No.91, Magersari, Panjunan, Kec. Kota Kudus, Kabupaten Kudus,...
WhatsApp: 0817839777 Jl. Pemuda No.90-92, Kembangsari, Kec. Semarang Tengah, Kota Semarang, Jawa Tengah 50133
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers