Technical Article

Migration Guide: Migrating to SQL Server 2012 Failover Clustering and Availability Groups from Prior Clustering and Mirroring Deployments

This paper provides guidance for customers who prior to SQL Server 2012 have deployed SQL Failover Clustering for local high availability and database mirroring for disaster recovery, and who want to migrate to SQL Server AlwaysOn. It describes the corresponding SQL Server AlwaysOn scenario and the migration paths to SQL Server AlwaysOn. It also contains the important knowledge and considerations that you must know in order to successfully migrate to a HADR solution based on SQL Server AlwaysOn technology, which implements AlwaysOn Failover Cluster Instances for high availability and AlwaysOn Availability Groups for disaster recovery.

External Article

Generating Data for Database Tests

It is more and more essential for developers to work on development databases that have realistic data in both type and quantity, but without using real data. It isn't exactly easy, even with third-party tools to hand. Phil Factor shows how it can be done, taking the classic PUBS database and giving it a more realistic set of data.

External Article

SQLServerCentral Webinar #17: Monitoring your SQL Server Instances

Join SQL Server MVP Brad McGehee to learn why it is so important to monitor your SQL Server instances and what you should consider when starting out. This webinar will also show you how you can use Red Gate's SQL Monitor for SQL Server monitoring and will include an overview of the new features released in v3.0, including the ability to create your own custom metric definition and to support different access permissions.

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Question of the Day

Adding new column with DEFAULT

Which number will the COUNT() return after executing the following statements:

DROP TABLE IF EXISTS #test;
CREATE TABLE #test (id INT)
INSERT INTO #test (id)
SELECT *
  FROM GENERATE_SERIES(1, 3) AS gs
;

ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0;
go
UPDATE #test SET flag = 0 WHERE id = 1
UPDATE #test SET flag = 1 WHERE id = 2

INSERT INTO #test (id) VALUES (4)

SELECT COUNT(*)
  FROM #test AS t
 WHERE flag = 0
 

See possible answers