Let's Fix a Password Problem
Grant discusses the need for password managers to help prevent security issues between different accounts.
2020-01-15
274 reads
Grant discusses the need for password managers to help prevent security issues between different accounts.
2020-01-15
274 reads
Today Kendra talks about two of the online options used when working with indexes.
2020-01-14
350 reads
2020-01-13
271 reads
2020-01-11
288 reads
2020-01-10
314 reads
Cowboy coding can be a problem, and in a case Steve talks about, a temptation for someone to get more work.
2020-01-08
514 reads
Steve thinks one of the ways you can stand out with your resume or CV is by writing well and attracting the attention of hiring managers.
2020-01-07
176 reads
Steve reminds you to be careful of taking shortcuts, as these can compromise security. Automation and DevOps might help you avoid mistakes.
2020-01-06
288 reads
This week Steve talks about the ways in which comments are important in our code.
2020-01-04
290 reads
Microsoft has spent years working on building a reliable and dependable patch process for their software. While some products have had more sporadic updates, SQL Server has moved to a fairly regular schedule. Not quite a predictable "Patch Tuesday" schedule, but you can count on a CU arriving every month or two for SQL Server. […]
2020-01-03
821 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
Comments posted to this topic are about the item Is Fabric a Reliable Service...
hi , a new user wants to be able to add sql agent jobs...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers