Conditionally Order By Different Column
Order records based on a different column depending on which absolute value is greater.
2018-10-01 (first published: 2018-09-26)
646 reads
Order records based on a different column depending on which absolute value is greater.
2018-10-01 (first published: 2018-09-26)
646 reads
2018-09-13
5,058 reads
Didn't find anything, so hope this will help someone with similar need.
Note I did a similar set-based version, and unless the input is more towards non-zeros in all eight 2-byte fields, the set-based performs not as well
2018-09-19 (first published: 2018-09-12)
601 reads
2018-09-06
950 reads
Producing hierarchies from SQL tables can necessitate joining a table to itself. This article will explain how you can do this.
2020-03-06 (first published: 2018-08-30)
24,786 reads
Handling weekends can be tricky in SQL. This article shows you how to Count the Number of Weekend Days between Two Dates
2020-10-16 (first published: 2018-08-23)
12,636 reads
On some occasions you will need to aggregate Data for the Last Day of the Month. This article explains how.
2020-04-03 (first published: 2018-08-16)
6,899 reads
2018-08-14
1,120 reads
Sometimes you need to output blank lines
- in effect displaying Records for Missing Data. This article explains how to use a CTE to do this
2018-08-09
4,747 reads
Comparing year on year sales is a fundamental requirement in much commercial analysis - here you learn how to do this in SQL
2018-08-02
3,308 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers