2009-02-06
4,616 reads
T-SQL
2009-02-04
4,596 reads
SQL Function : Find ‘X’ Business Days in the Future
Many of us deal in date calculations and separating business days from calendar days is always a challenge. New author J Gravelle brings us a new article that talks about this subject as a way of ensuring SLAs are met.
2009-02-04
10,837 reads
2009-02-02
4,552 reads
Calculate Distance in Miles from Latitude and Longitude
A fast and accurate way to calculate the distance in miles between two points, based on the latitudes and longitudes.
2014-09-26 (first published: 2009-01-31)
9,213 reads
Hierarchies in SQL
One very common structure that needs to be handled in T-SQL is the hierarchy. One of our prominent members of the community discusses how you can handle hierarchies in SQL Server.
2010-12-10 (first published: 2009-01-28)
33,910 reads
Solving the “Running Totals” Problem in SQL Server 2005 with Partitioned Tables
Lynn Pettis gives us a look at a new way to solve a T-SQL problem.
2009-01-27
12,374 reads
2009-01-26
4,842 reads
2009-01-22
4,652 reads
Missing row numbers
I had a request from a client who prints a lot of cheques each month and there control over the cheques went a bit haywire. The requested me to create some controls in their system to make sure that the cheques are use in cheque number sequence.
2009-01-20
1,125 reads
Blogs
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Forums
SQL Art, Part 4: Happy 4th of July — A British DBA's Guide to Celebrating a War We Don't Talk About
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
Concurrency and Baseline Control: Level 5 of the Stairway to Reliable Database Deployments
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Spending Time in the Office
Comments posted to this topic are about the item Spending Time in the Office
Question of the Day
Multiple Values Inserted
I have this code on SQL Server 2022. What happens when it runs all at once?
DROP TABLE IF EXISTS dbo.Commission GO CREATE TABLE dbo.Commission (id INT NOT NULL IDENTITY(1,1) CONSTRAINT CommissionPK PRIMARY KEY , salesperson VARCHAR(20) , commission VARCHAR(20) ) GO INSERT dbo.Commission ( salesperson, commission) VALUES ( 'Brian', 12 ), ( 'Brian', 'None' ) GOSee possible answers