2009-05-11
4,535 reads
2009-05-11
4,535 reads
2009-05-07
4,155 reads
2009-05-06
3,966 reads
SQL Server database engine doesn't have a MEDIAN() aggregate function. This is probably because there are several types of median, such as statistical, financial or vector medians. Calculating Medians are essentially a row-positioning task, since medians are the middle value of an ordered result. Easy to do in SQL? Nope. Joe Celko explains why.
2009-05-06
2,024 reads
2009-05-05
4,796 reads
2009-05-04
4,506 reads
Reports all running requests along with the request's identifying information (SPID, login etc), current resource consumption, query batch text, statement text, and XML query plan.
2010-05-24 (first published: 2009-05-01)
5,327 reads
2009-05-01
4,497 reads
2009-04-30
4,064 reads
2009-04-29
4,508 reads
By Steve Jones
Thanks to everyone who attended my sessions today at SQL Saturday Boston 2025. I’ve...
SQL Server 2025 introduces native support for vector data types and external AI models....
By Steve Jones
Fear is fueled by a lack of imagination. The antidote to fear is not...
I'm building ETL packages in SSIS. My data comes from an OLE DB Source...
Comments posted to this topic are about the item Building AI Governance and Policies-...
Why is sql doing a full scan VS seeking on the index? I've included...
The DBCC CHECKIDENT command is used when working with identity values. I have a table with 10 rows in it that looks like this:
TravelLogID CityID StartDate EndDate 1 1 2025-01-11 2025-01-16 2 2 2025-01-11 2025-01-16 3 3 2025-01-11 2025-01-16 4 4 2025-01-11 2025-01-16 5 5 2025-01-11 2025-01-16 6 6 2025-01-11 2025-01-16 7 7 2025-01-11 2025-01-16 8 8 2025-01-11 2025-01-16 9 9 2025-01-11 2025-01-16 10 10 2025-01-11 2025-01-16The docs for DBCC CHECKIDENT say this if I run with only the table parameter: "If the current identity value for a table is less than the maximum identity value stored in the identity column, it is reset using the maximum value in the identity column. " I run this code:
DELETE dbo.TravelLog WHERE TravelLogID >= 9 GO DBCC CHECKIDENT(TravelLog, RESEED) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-09-14', '2025-09-17') GOWhat is the identity value for the new row inserted by the insert statement above? See possible answers