2010-03-19
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2010-03-19
3,308 reads
We have recently made a few changes in our newsletter sending process and been working with Yahoo to ensure delivery. If you are just receiving this newsletter to a Yahoo account, welcome.
2010-02-10
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2009-12-24
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2009-11-04 (first published: 2009-10-16)
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We have expanded our forums with a new Question and Answer site based on the StackOverflow codebase. Please feel free to visit.
2009-10-12 (first published: 2009-10-09)
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2009-09-11
4,142 reads
SQLServerCentral is changing usernames for some of our members in an effort to clean things up. Read more about what will be happening on Tuesday, Sept. 15, 2009.
2009-09-14 (first published: 2009-09-11)
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SQLServerCentral is hosting an opening night party at the 2009 PASS Summit. Read more about this and learn how to get a ticket.
2009-08-19
88 reads
Get some details about the 2009 SQLServerCentral party at the PASS Summit in November.
2009-10-29 (first published: 2009-07-20)
2,190 reads
2009-07-09
29 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers