2009-01-02
2,915 reads
2009-01-02
2,915 reads
SQL Server 2008 has introduced a new way to store data for columns that contain excessive NULL values called Sparse Columns. What this means is that when you declare a column as Sparse and any time a NULL value is entered in the column it will not use any space. Is there a way to identify what columns would make a good candidate for this without having to analyze each column individually?
2008-12-15
2,633 reads
This article about MERGE DML Statement in SQL SERVER 2008 and how to implements it and several examples
2008-12-08
4,163 reads
This 490-page document covers the essential phases and steps to upgrade existing instances of SQL Server 2000 and 2005 to SQL Server 2008 by using best practices. These include preparation tasks, upgrade tasks, and post-upgrade tasks. It is intended to be a supplement to SQL Server 2008 Books Online.
2008-12-03
3,401 reads
2008-12-02
3,090 reads
New features in SQL Server 2008 Reporting Services mean improved charting and increased memory. Learn more about SSRS performance upgrades in SQL 2008.
2008-11-28
4,708 reads
This article shows how to use the SQL Server 2008 Upgrade Advisor Tool to improve the SQL Server 2008 upgrade experience
2008-11-26
1,791 reads
Thomas has been running SQL Server 2008 live in production for over 1 year as part of the Microsoft Early Adopter Program. Below is the full interview I conducted with him about his experience with SQL Server 2008.
2008-11-25
2,200 reads
This article shows how to use the GROUPING SETS feature in SQL Server 2008
2008-11-19
3,390 reads
This article introduces us to the new Spatial Data Types in SQL Server 2008
2008-11-19
7,710 reads
By Steve Jones
I’m not sure I knew identity column values could not be updated. I ran...
By Steve Jones
We had an interesting discussion about deployments in databases and how you go forward...
By ChrisJenkins
You could be tolerating limited reporting because there isn’t an off the shelf solution...
I have mentioned this several times over several years. Can someone please help me...
SELECT COUNT(DISTINCT Component) AS Found FROM tblComponents WHERE(Component NOT LIKE '%[a-z]%') AND(LTRIM(RTRIM(Component)) = 'GM13622')...
Comments posted to this topic are about the item Remotely Engineer Fabric Lakehouse objects:...
In a SQL Server 2025 table, called Beer, I have this data:
BeerIDBeerName 1Becks 2Fat Tire 3Mac n Jacks 4Alaskan Amber 8KirinI run this code:
SELECT JSON_OBJECTAGG(
BeerID: BeerName )
FROM beer;
What are the results? See possible answers