2023-09-01
462 reads
MS SQL Server Agent
Create an HTML Report on the Status of SQL Server Agent Jobs
SQL Server jobs are an integral part of any SQL Server environment. These jobs run a predefined set of tasks and commands at specified intervals, ensuring the database is up-to-date and performing optimally. As a database administrator, it is essential to regularly monitor the status of SQL Server jobs. One way to do this is […]
2023-05-03
8,267 reads
MSSQL Server AlwaysON: Get alerted for inconsistencies in logins, jobs and databases
This script will create the necessary login and linked servers on a given availability replica. Please ensure that the script is executed on all the replicas.
2022-02-22 (first published: 2022-01-25)
7,724 reads
Compare MS SQL Agent jobs on two servers
During a database migration or a side by side database upgrade project we need to migrate the MS SQL Server Agent jobs. This script compare jobs by names and shows unmatched jobs.
2018-01-25 (first published: 2018-01-20)
3,347 reads
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The Tightly Linked View
Comments posted to this topic are about the item The Tightly Linked View
Question of the Day
The Tightly Linked View
I try to run this code on SQL Server 2022. All the objects exist in the database.
CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
cl.CityName,
o.OrderID,
o.Customer,
o.OrderDate,
o.CustomerID,
o.cityId
FROM dbo.CityList AS cl
INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
@OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
DECLARE @city VARCHAR(50);
SELECT @city = os.CityName
FROM dbo.OrderShipping AS os
WHERE os.OrderID = @OrderID;
RETURN @city;
END;
go
What is the result? See possible answers