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SQLServerCentral Editorial

The Top 5 Technologists

  • Editorial

There's a common party question about which 5 people would you invite to a dinner party? Often this is amended to include living or dead people, and it's often interesting to hear people tell you who they'd invite and why. Since most of the people reading this work in technology in some way, I was […]

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2023-02-24

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External Article

The Data Center that Exploded

  • Article

A while back, in a Simple-Talk editorial meeting, someone bet Phil Factor that he couldn't come up with a Halloween story. To our surprise he said he could, as long as he didn't have to keep to the strict literal truth. In the end, he came up with a story about a story, and it is true that he first told the story in a data Centre at Halloween!

2025-01-01 (first published: )

10,375 reads

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Question of the Day

The Tightly Linked View

I try to run this code on SQL Server 2022. All the objects exist in the database. 

CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
       cl.CityName,
       o.OrderID,
       o.Customer,
       o.OrderDate,
       o.CustomerID,
       o.cityId
 FROM dbo.CityList AS cl
 INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
    @OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
    DECLARE @city VARCHAR(50);
    SELECT @city = os.CityName
    FROM dbo.OrderShipping AS os
    WHERE os.OrderID = @OrderID;
    RETURN @city;
END;
go
What is the result?

See possible answers