DataTypes

External Article

The Many Benefits of Money…Data Type!

  • Article

Our initial reason for looking at the money data type can be found within the Precision Considerations for Analysis Services Users white paper. In this white paper, we provide extensive examples of the types of precision issues when your SQL relational data source and your Microsoft® SQL Server® Analysis Services cube have different non-matching data types (e.g., if you query one way you get the value 304253.3251, but run the query in another way and you get the value 304253.325100001).

2008-10-02

2,761 reads

Blogs

The Book of Redgate: We Value Teams

By

This value is something that I still hear today: our best work is done...

Troubleshooting TempDB Log Full Errors When SSMS Won’t Connect

By

Have you ever received the dreaded error from SQL Server that the TempDB log...

Accelerating AI with Confidence: Why Microsoft Purview is Key to Responsible Innovation

By

Artificial intelligence is no longer a distant concept. It is here, embedded in the...

Read the latest Blogs

Forums

Planning for tomorrow, today - database migrations

By John Martin

Comments posted to this topic are about the item Planning for tomorrow, today -...

Bottlenecks on SQL Server performance

By runarlan

We have a BI-application that connects to input tables on a SQL Server 2022...

Is there some good routines for updating SQL Server database objects with GitHub

By Rod at work

At work we've been getting better at writing what's known as GitHub Actions (workflows,...

Visit the forum

Question of the Day

The Tightly Linked View

I try to run this code on SQL Server 2022. All the objects exist in the database. 

CREATE OR ALTER VIEW OrderShipping
AS
SELECT cl.CityNameID,
       cl.CityName,
       o.OrderID,
       o.Customer,
       o.OrderDate,
       o.CustomerID,
       o.cityId
 FROM dbo.CityList AS cl
 INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID
GO
CREATE OR ALTER FUNCTION GetShipCityForOrder
(
    @OrderID INT
)
RETURNS VARCHAR(50)
WITH SCHEMABINDING
AS
BEGIN
    DECLARE @city VARCHAR(50);
    SELECT @city = os.CityName
    FROM dbo.OrderShipping AS os
    WHERE os.OrderID = @OrderID;
    RETURN @city;
END;
go
What is the result?

See possible answers