Cloning SQL Server Instances with Containers
Learn how containers and WinDocks can be used to quickly provision copies of databases.
2018-12-31
2,186 reads
Learn how containers and WinDocks can be used to quickly provision copies of databases.
2018-12-31
2,186 reads
Learn how to deploy Reporting Services into a container with Windocks.
2018-10-04
8,724 reads
Learn how you can get a SQL Server 2017 container working with Docker and Windocks.
2018-08-28
1,252 reads
Learn how containers can help with database development.
2018-06-07
804 reads
In this case study, see how database containers can help improve a QA process.
2017-03-16
678 reads
Get the basics of what a container is and how this can work with SQL Server.
2017-01-06
9,858 reads
Containers promise to make applications more portable and efficient. The technology, originally based on Linux's cgroups, provides a way of running several applications as modular, platform-agnostic packages in isolation on the same server. Docker's open-source approach to containers has dominated the market, and Microsoft is producing its own equivalent Windows system. What next? Will Containers replace VMS? Robert Sheldon investigates.
2015-02-18
8,746 reads
By Steve Jones
Here are the resources for my talk at Day of Data Boston. Slides –...
By Steve Jones
I’ve covered the values in a number of previous posts on the Book of...
By Arun Sirpal
When the evidence names the database, it says so. When it doesn’t, it stops....
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers