AlwaysON Availability Group and Jobs Part 1
In this article (consist from 2 parts) , I will be focusing on one of the practical solutions for management of internal SQL Server jobs in AlwaysOn Availability Groups scenarios.
2017-05-10
6,289 reads
In this article (consist from 2 parts) , I will be focusing on one of the practical solutions for management of internal SQL Server jobs in AlwaysOn Availability Groups scenarios.
2017-05-10
6,289 reads
2017-01-27
1,017 reads
2017-01-12
939 reads
2016-11-25
977 reads
Aaron Bertrand reveals details about the changes to Availability Groups that will ship in the next major version: SQL Server 2016.
2016-01-14
6,823 reads
If you are deploying SQL Server Availability Groups, one of the important aspects of a successful deployment is monitoring the synchronization of the secondary replica databases with the primary replica - but there are multiple ways to do this. Jonathan Kehayias goes through each, explaining their different benefits and drawbacks.
2015-09-17
2,771 reads
Tom Stringer (@SQLife) was working on some HADR testing for a customer to simulate many availability groups and introduce significant load into the system to measure overhead and such. In his quest to do that he was seeing behavior that he couldn’t really explain and so worked with him to uncover what was happening under the covers.
2013-07-23
3,177 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
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I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers