AlwaysON Availability Group and Jobs Part 1
In this article (consist from 2 parts) , I will be focusing on one of the practical solutions for management of internal SQL Server jobs in AlwaysOn Availability Groups scenarios.
2017-05-10
6,264 reads
In this article (consist from 2 parts) , I will be focusing on one of the practical solutions for management of internal SQL Server jobs in AlwaysOn Availability Groups scenarios.
2017-05-10
6,264 reads
2017-01-27
1,016 reads
2017-01-12
935 reads
2016-11-25
974 reads
Aaron Bertrand reveals details about the changes to Availability Groups that will ship in the next major version: SQL Server 2016.
2016-01-14
6,823 reads
If you are deploying SQL Server Availability Groups, one of the important aspects of a successful deployment is monitoring the synchronization of the secondary replica databases with the primary replica - but there are multiple ways to do this. Jonathan Kehayias goes through each, explaining their different benefits and drawbacks.
2015-09-17
2,771 reads
Tom Stringer (@SQLife) was working on some HADR testing for a customer to simulate many availability groups and introduce significant load into the system to measure overhead and such. In his quest to do that he was seeing behavior that he couldn’t really explain and so worked with him to uncover what was happening under the covers.
2013-07-23
3,177 reads
When I put together the invitation for T-SQL Tuesday #202, I wasn't sure what...
By Steve Jones
My life has some crazy travel stretches for sure. Between speaking, office visits, customer...
In Part 1, we saw how ‘Vamana’ represents vectors as nodes, connects them with...
Comments posted to this topic are about the item Server-Level Table sizes
Comments posted to this topic are about the item Optional Parameter Plan Optimization in...
There is a table tmp_tab:
CREATE TABLE tmp_tab ( id int, val int );
INSERT INTO tmp_tab VALUES (1, 1), (2, NULL), (3, 3), (4, 4), (5, 5);You want to order the rows ids by the following expression:
ISNULL(val, id) + 1Which of the following queries produces the expected ordering and why? (Select all correct) See possible answers