Data Warehouse Fast Track for SQL Server 2016
Microsoft Data Warehouse Fast Track for SQL Server 2016 is a joint effort between Microsoft and its hardware partners to...
2016-10-19
973 reads
Microsoft Data Warehouse Fast Track for SQL Server 2016 is a joint effort between Microsoft and its hardware partners to...
2016-10-19
973 reads
I’ll be attending the 2016 Pass Summit as a part of the Redgate Software crew. I’m not speaking this year,...
2016-10-19
465 reads
Recently I gave an introductory webinar on how to build an auditing framework for SQL Server. The focus was for...
2016-10-19
508 reads
For anyone who wasn’t aware SQLCMD is a command line tool for running T-SQL statements and scripts. Before anyone says...
2016-10-19
1,276 reads
2016-10-18
9 reads
2016-10-18
8 reads
2016-10-18
11 reads
2016-10-18
25 reads
Prakash will walk you through a centralized process using PowerShell where the key information collected, organized and sent via HTML formatted email, provides consolidated view of SQL server along...
2016-10-18
25 reads
Prakash will walk you through a centralized process using PowerShell where the key information collected, organized and sent via HTML...
2016-10-18
585 reads
By Steve Jones
Here are the resources for my talk at Day of Data Boston. Slides –...
By Steve Jones
I’ve covered the values in a number of previous posts on the Book of...
By Arun Sirpal
When the evidence names the database, it says so. When it doesn’t, it stops....
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers