MCITP 1 Down 3 To Go
Yesterday I posted a quick blurb about my certification plans this year. Well, ok not full blown plans , but you...
2011-05-20
709 reads
Yesterday I posted a quick blurb about my certification plans this year. Well, ok not full blown plans , but you...
2011-05-20
709 reads
Yesterday I posted a quick blurb about my certification plans this year. Well, ok not full blown plans , but you get the gist. I announced that I would...
2011-05-20
2 reads
Last year (and this year too) I had set the goal to renew my certification. I failed miserably at it...
2011-05-19
514 reads
Last year (and this year too) I had set the goal to renew my certification. I failed miserably at it last year with the exception that I at least...
2011-05-19
Come one, come all!! Oh wait, it’s too late now. I just finished giving my presentation to the DBA VC...
2011-05-11
660 reads
Come one, come all!! Oh wait, it’s too late now. I just finished giving my presentation to the DBA VC (virtual chapter). There was good attendance and there were...
2011-05-11
This is a quick reminder of the upcoming May meeting for the Las Vegas SQL Server Users Group. We will...
2011-05-10
521 reads
This is a quick reminder of the upcoming May meeting for the Las Vegas SQL Server Users Group. We will be meeting on May 12, 2011 at the usual...
2011-05-10
4 reads
As a part of my careers goals, I am trying to remain involved in the community through various engagements and...
2011-05-10
677 reads
As a part of my careers goals, I am trying to remain involved in the community through various engagements and events. Recently, I was able to present to the...
2011-05-10
1 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers