SQL Statistics – another Spin
I was reading a blog by Pinal Dave that was about using catalog views to obtain information about stats for...
2011-07-01
662 reads
I was reading a blog by Pinal Dave that was about using catalog views to obtain information about stats for...
2011-07-01
662 reads
I was reading a blog by Pinal Dave that was about using catalog views to obtain information about stats for the entire database. While reading the blog, I was...
2011-07-01
13 reads
I have a new tune stuck in my head now. It got stuck there this afternoon shortly after my computer...
2011-06-30
1,631 reads
I have a new tune stuck in my head now. It got stuck there this afternoon shortly after my computer was forced into a reboot. I was in the...
2011-06-30
3 reads
In my last post concerning my certification journey I said I may post a study guide. I have thought it...
2011-06-30
4,762 reads
In my last post concerning my certification journey I said I may post a study guide. I have thought it over and a sweetened condensed version of some of...
2011-06-30
2 reads
Despite my desire to do one exam a week in pursuit of the MCITP Certifications for DBA and Developer in...
2011-06-27
757 reads
Despite my desire to do one exam a week in pursuit of the MCITP Certifications for DBA and Developer in SQL 2008, other things came up that have slowed...
2011-06-27
When I first read this article, I thought to myself “I have no clue on this one. What could I...
2011-06-14
728 reads
There are three types of disasters that are seldom expected. Read about the fun of dealing with these different types of disasters.
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Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers