How to Make Sure Your Clients Can Connect to a Multi-Subnet Cluster
When you set up a multi-subnet cluster, whether it’s a Failover Cluster Instance or an Availability Group, you need to...
2014-09-29
980 reads
When you set up a multi-subnet cluster, whether it’s a Failover Cluster Instance or an Availability Group, you need to...
2014-09-29
980 reads
I am putting up an abnormal Saturday morning blog post in support of the actions taken by the PASS Board...
2014-09-27
595 reads
This morning I received an email (really 3 emails) about an extension for voting for the Board of Directors giving...
2014-09-27
779 reads
Photo credit – Mike Lynch
A good cure to a creepy doll is a good old post that is still useful. In...
2014-09-26
795 reads
I had another piece that looked at some issues with PASS slated for today, but it’s been a tough morning....
2014-09-26
1,033 reads
While I was at the VMWare HQ getting some amazing training a few weeks ago, we had the opportunity to...
2014-09-26
669 reads
Continuing on with things that PASS does well, since I want to be balanced, I wanted to talk about volunteers....
2014-09-26
903 reads
It’s Friday, time to look back at the most popular RealSQLGuy posts of the week. Because it’s Friday and you’re...
2014-09-26
453 reads
2014-09-26
8 reads
2014-09-26
10 reads
By SQLPals
How to Clear the SSMS Cache (SSMS 21 and Later) Updated...
By Arun Sirpal
“What exactly did it do on my server?” is the first question a DBA...
By James Serra
Microsoft shared a broad set of Fabric, Power BI, and SQL updates at FabCon...
Comments posted to this topic are about the item Let's Talk Certifications
Comments posted to this topic are about the item The Hidden Security Risks of...
Comments posted to this topic are about the item The Empty Aggregate
I have this table in a SQL Server 2025 database:
CREATE TABLE [dbo].[CustomerOrder] ( [OrderID] [int] NULL, [CustomerID] [int] NULL, [total] [money] NULL ) ON [PRIMARY] GOWhat is returned from this code? (answers are for the sum and then the count)
SELECT SUM(total) AS sum,
COUNT(total) AS count
FROM dbo.CustomerOrder;
See possible answers