Tech Books: Caveat Emptor
These days, we have a myriad of ways to judge whether any given product – like, say, a book on SQL...
2011-01-05
774 reads
These days, we have a myriad of ways to judge whether any given product – like, say, a book on SQL...
2011-01-05
774 reads
Hello and welcome to the first T-SQL Tuesday of 2011!
2010 was a great year for T-SQL Tuesdays, dreamed up and...
2011-01-04
1,285 reads
The days are just flying. I have to admit: I may have missed a day or two in the rush...
2011-01-03
486 reads
Howdy all…as is so often the case, I’m studying something – Powershell – and I’m in need of a reference to help...
2011-01-03
2,684 reads
It’s entirely fair to say that the highlight of my professional year is the PASS Summit in Seattle, and the...
2010-12-30
1,793 reads
I’m looking for the attribution for a quote – it’s something I first heard from Sean, and we say it all...
2010-12-29
500 reads
This is a companion piece to the MidnightDBA video T-SQL: CASE Statement.
In short, a CASE statement is a simplified set...
2010-12-28
2,709 reads
Well, my brain has increased by 12.4% in terms of SQL knowledge this week, as a direct result of my...
2010-12-28
758 reads
Rule: No Sushi with Adam within 24 hours of session
I’m inspired by Brent Ozar‘s and Andy Leonard‘s sharing of their PASS...
2010-12-23
776 reads
Hooboy…the super-structured format of the first two RTFM365 posts just isn’t sustainable for me. I’m going to have to go...
2010-12-20
659 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers