Opinions about PASS
There has been quite a discussion today on the direction of PASS (the Professional Association for SQL Server) and some...
2009-10-22
679 reads
There has been quite a discussion today on the direction of PASS (the Professional Association for SQL Server) and some...
2009-10-22
679 reads
Anyone who has an Internet connection has kept up with PASS-related news during the past couple of weeks is keenly...
2009-10-22
787 reads
I hate to start a blog war, but maybe there's one going on. The recent PASS 2009 election concluded a...
2009-10-22
1,838 reads
I was chatting on FaceBook today with a guy from my church who is learning to be a network engineer. He's...
2009-10-22
928 reads
Picking up from yesterday, once we got through the confusion of the room changes everything settled down. I checked the...
2009-10-21
615 reads
No, I’m not talking about a Dickens novel. I’m talking about the number of characters in a string. I had...
2009-10-21
1,639 reads
Mike Walsh, who is a PASS volunteer, has done a nice job organizing the PASS Summit Birds of a Feather...
2009-10-21
914 reads
I’ll be on the Twitter Bingo card along with a lot of other great SQL Server folks at Pass! Quest...
2009-10-21
575 reads
My presentation and sample files from SQLSaturday in Orlando are now online for you to download. Check them out at...
2009-10-21
390 reads
Hey there folks. I finally was able to get my persona domain name from a squatter who has been holding...
2009-10-21
396 reads
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
By Zikato
A cryptic message, a book cipher hidden in art provenance records, and a trail...
Title pretty much says it all - can this be done? I've tried several...
Comments posted to this topic are about the item BIT_COUNT II
Comments posted to this topic are about the item I Can't Make You Learn
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers