Partitioning 5: The extra partition
So, we’ve set up a table with table partitioning on the RIGHT for CreationDate. We defined 11 partitions, and in...
2019-02-18
169 reads
So, we’ve set up a table with table partitioning on the RIGHT for CreationDate. We defined 11 partitions, and in...
2019-02-18
169 reads
I’m super excited about the fact I’ll be speaking at SQLBits this year. It’s my first time as a speaker...
2019-02-18
121 reads
There are plenty of scripts out there that can show you the waits that are occurring on your server, however,...
2019-02-18
169 reads
I’ll be in South Florida again this year and will stay over as usual for a couple days of vacation....
2019-02-18
163 reads
I’ll be in South Florida again this year and will stay over as usual for a couple days of vacation. I see Brent is attending; I’ll have to make...
2019-02-18
12 reads
(Be sure to checkout the FREE SQLpassion Performance Tuning Training Plan - you get a weekly email packed with all the...
2019-02-18
128 reads
New week, new challenges! Great to see you again. We are always here Monday morning! No need to check earlier...
2019-02-18
112 reads
Microsoft’s Azure Databricks is an advanced Apache Spark platform that brings data and business teams together. In this introductory article,...
2019-02-17
496 reads
Microsoft’s Azure Databricks is an advanced Apache Spark platform that brings data and business teams together. In this introductory article, we will look at what the use cases for...
2019-02-17
20 reads
Power BI Desktop February 2019 Feature Summary Preview of new Key Influencers visual and much more… The February release of...
2019-02-17
113 reads
By Steve Jones
I wrote about learning today for the editorial: I Can’t Make You Learn. I...
By ReviewMyDB
Fabric has CI/CD built in, but if you've tried to use it for database...
By Steve Jones
attriage – n. the state of having lost all control over how you feel...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers