PASS Update #31 (Election Prep)
Sometime soon we’ll start the process of the 2010 PASS election, with three seats on the Board of Directors being...
2010-05-04
400 reads
Sometime soon we’ll start the process of the 2010 PASS election, with three seats on the Board of Directors being...
2010-05-04
400 reads
Since I am very interested in various PC-based hardware, and I make an effort to stay current on new developments,...
2010-05-04
858 reads
My first post in my replication series gave a brief overview of replication, before I dive into setting up and...
2010-05-04
7,146 reads
The free 24 Hours of PASS event will held May 19 & 20, and includes 24 different one hour presentations on...
2010-05-03
407 reads
A couple weeks ago I wrote about testing the LinkedIn polling capability, putting up this poll:
The response rate wasn’t great,...
2010-05-03
318 reads
The Issue
Being involved in PASS and the SQL Server community via blogging and Twitter, I get to see and hear...
2010-05-03
1,030 reads
Well, I managed to finish up my series that featured a DMV query every day during the month of April....
2010-05-03
2,902 reads
The free 24 Hours of PASS event will be held on May 19-20, and includes 24 different one hour presentations...
2010-05-03
530 reads
I have worked with a lot of organizations who just have just a small handful of SQL Server instances. In...
2010-05-03
2,952 reads
In SQL Server there are two stored procedures that help one to determine the size of a table. One is...
2010-05-03
864 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers