2011-06-13
2011-06-13
This past Saturday June 11th, 2011 I had the opportunity to co-present at SharePoint Saturday Tampa thanks to a special invitation...
2011-06-13
1,074 reads
A continuation of the data dictionary discussion with information about how the documentation is done.
Today I’m going to continue discussing...
2011-06-13
1,491 reads
After nearly five and half years, I left NewsGator Technologies for a new position as a Database Architect at Avalara,...
2011-06-13
846 reads
Working at a client site, that in itself is good to say, I ran into a set of circumstances that...
2011-06-13
639 reads
Note: This is a good, bad, and ugly post. We took some chances, got some things right, got more than...
2011-06-13
993 reads
I am very exicted to be speaking at the San Antonio PASS chapter SALSSA! It’s been way to long and...
2011-06-13
608 reads
Bluntly put, this is something that you always want to be taking advantage of.
As a Database Administrator I’m always on...
2011-06-13
660 reads
For many Analysis Services developers building dimensions with many attributes and hierarchies is something that comes as second nature to...
2011-06-13
5,896 reads
Well it’s been an exciting couple of weeks leading up to this course. We have tweaked what we could in...
2011-06-13
633 reads
A RAG pipeline that answers questions in the demo is not the same thing...
By Steve Jones
“A multitude of bad ideas is necessary for one good idea” – from Excellent...
Yesterday I gave a talk for MSSQLTips called “Building a DBA Agent for Your...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Comments posted to this topic are about the item Looking for New Blood
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers