Learning Transactional Replication
I have been working on a new skill this week and that is implementing transactional replication. I am of course...
2011-08-24
707 reads
I have been working on a new skill this week and that is implementing transactional replication. I am of course...
2011-08-24
707 reads
This is a bit off-topic, but I wanted to mention a great tool for beginners to learn how to program. ...
2011-08-24
2,074 reads
Our most recent Board meeting was Aug 11 & 12 in Ft Lauderdale (located so we could attend SQLSaturday on Saturday)....
2011-08-24
613 reads
As is the case with many of my topics of late, I came across this one by helping somebody else....
2011-08-24
2,985 reads
As is the case with many of my topics of late, I came across this one by helping somebody else. In SQL, we should be well aware of Precision...
2011-08-24
22 reads
2011-08-24
8 reads
This series of Videos will walk through how to prepare existing windows 7 machine to test and validate active/active node...
2011-08-24
1,306 reads
2011-08-24
7 reads
2011-08-24
45 reads
2011-08-24
10 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
WhatsApp CS 628218520154 Jl. Suryopranoto No.40, RT.12/RW.7, Petojo Utara, Kecamatan Gambir, Kota Jakarta Pusat,...
WhatsApp CS 628218520154 Jl. Pegangsaan Timur No.1, Cikini, Kec. Menteng, Kota Jakarta Pusat, Daerah...
WhatsApp CS 628218520154 Jl. Pintu Air Raya No.36 Q, RT.6/RW.1, Ps. Baru, Kecamatan Sawah...
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers