2012-07-15
1,151 reads
2012-07-15
1,151 reads
Overall I find the site to be useful and responsive, but sometimes I see small things that I wish were...
2012-07-15
652 reads
Introducing Windows Server 2012 - can be downloaded for free here.
This book provides the early, high-level information you need to begin preparing...
2012-07-14
2,273 reads
This post is part of a blog series which focuses on translating compatibility views in SQL Server to their respective...
2012-07-13 (first published: 2012-07-04)
2,689 reads
I bought a USB hard disk recently that I wanted to use to backup some VMware Workstation and some Hyper-V...
2012-07-13
1,009 reads
We’re drawing to the end of our third season of DBAs@Midnight (our weekly webshow by DBAs, for DBAs), and to the...
2012-07-13
758 reads
18456 is probably one of the most common errors people come across and in this article we try to cover...
2012-07-13
801 reads
As a DBA, it is important for all of us to get real time alert on various issues in our...
2012-07-13
6,758 reads
Fujitsu has submitted a new TPC-E benchmark for a two socket, Sandy Bridge-EP system that had a tpsE score of...
2012-07-13
1,950 reads
Not another comma separated string blog post I hear you say! I know that this topic has probably been done...
2012-07-13
6,837 reads
By Arun Sirpal
“What exactly did it do on my server?” is the first question a DBA...
By James Serra
Microsoft shared a broad set of Fabric, Power BI, and SQL updates at FabCon...
By Steve Jones
No, I’m not quitting or retiring. Just going on vacation, but I leave tonight...
Comments posted to this topic are about the item Let's Talk Certifications
Comments posted to this topic are about the item The Hidden Security Risks of...
Comments posted to this topic are about the item The Empty Aggregate
I have this table in a SQL Server 2025 database:
CREATE TABLE [dbo].[CustomerOrder] ( [OrderID] [int] NULL, [CustomerID] [int] NULL, [total] [money] NULL ) ON [PRIMARY] GOWhat is returned from this code? (answers are for the sum and then the count)
SELECT SUM(total) AS sum,
COUNT(total) AS count
FROM dbo.CustomerOrder;
See possible answers