Alexander Safronov

Sr. DBA @ Adams12 Five Star School District. Thornton, CO.
20 years of experience with SQL Server (from 6.0).

Technical Article

Migrate and Upgrade SQL Instance (2014/2016) to 2019 version with 1 click

The script includes these steps:   STEP 1: CREATE EMPTY Databases STEP 2 - CREATE Logins WITH SERVER ROLESPERMISSIONS STEP 3 - COPY LINKED SERVERS STEP 4 - COPY SERVER OPTIONS STEP 5 - COPY CREDENTIALS STEP 6 - COPY AGENT JOBS STEP 7 - COPY DB Mail STEP 8 - COPY CERTIFICATES STEP 9 […]

★ ★ ★ ★ ★ ★ ★ ★ ★ ★

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2020-05-22 (first published: )

1,197 reads

Technical Article

Migrate and Upgrade SQL Instance (2014/2016) to 2019 version with 1 click

The script includes these steps:   STEP 1: CREATE EMPTY Databases STEP 2 - CREATE Logins WITH SERVER ROLES\PERMISSIONS STEP 3 - COPY LINKED SERVERS STEP 4 - COPY SERVER OPTIONS STEP 5 - COPY CREDENTIALS STEP 6 - COPY AGENT JOBS STEP 7 - COPY DB Mail STEP 8 - COPY CERTIFICATES STEP 9 […]

★ ★ ★ ★ ★ ★ ★ ★ ★ ★

You rated this post out of 5. Change rating

2020-05-22 (first published: )

2,554 reads

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Question of the Day

Using CHOOSE()

We have this code that sets some status values and then queries them using the CHOOSE() function in SQL Server 2025.

CREATE TABLE Status
(
    StatusID INT,
    StatusDescription VARCHAR(20)
);
GO
INSERT dbo.Status
(
    StatusID,
    StatusDescription
)
VALUES
(0, 'Uncategorized'),
(1, 'Active'),
(2, 'Inactive'),
(3, 'Temp');

GO
SELECT CHOOSE(StatusID, 'Unknown', 'Active', 'Inactive', 'Temporary')
FROM Status;
When the SELECT runs, what is returned?

See possible answers