PASS Election Questions Answered 2
Today I am going to continue with my PASS Election Questions and Answers series. Here is where you can find...
2015-09-17
614 reads
Today I am going to continue with my PASS Election Questions and Answers series. Here is where you can find...
2015-09-17
614 reads
As we continue through the campaign period for this year’s PASS Board of Directors Election (Voting opens tomorrow morning), I...
2015-09-16
513 reads
The 2014 NomCom made some changes to how the election process works and it’s something you need to pay attention...
2015-09-15
514 reads
I’m going to hopefully show examples of some qualities I have that will benefit me if chosen as a board...
2015-09-14
565 reads
I built a brand new virtual machine running Windows 2012 R2 and SQL Server 2016 CTP 2.2 (the June edition). ...
2015-08-13
1,677 reads
On July 15th, 2015 I spoke to the PASS Architecture Virtual Chapter about AlwaysOn Failover Cluster Instances and AlwaysOn Availability...
2015-08-05
1,144 reads
Redgate will be hosting another SQL in the City event on the Monday right before the PASS Summit 2015. This...
2015-08-04
595 reads
The North Texas SQL Server User Group Board of Directors has decided to do something a little bit different for...
2015-07-30
1,080 reads
How could you possibly argue with getting 8 straight hours of SQL Server Performance training for FREE?
You can’t! Go check...
2015-07-20 (first published: 2015-07-14)
3,828 reads
I’ll be doing a precon for SQLSaturday #422 in Oklahoma City on August 28th, 2015 titled “Creating a High Availability and Disaster...
2015-07-15
758 reads
I’ve been thinking a lot lately about what it actually takes to make an...
By Steve Jones
Redgate is a for-profit company. We look to make money by building and selling...
I’ve uploaded the slides for my Techorama session Microsoft Fabric for Dummies and my...
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We create the following table and then insert some records in it:
create table t1 ( id int primary key, category char(1) not null, product varchar(50) ); insert into t1 values (1, 'A', 'Product 1'), (2, 'A', 'Product 2'), (3, 'A', 'Product 3'), (4, 'B', 'Product 4'), (5, 'B', 'Product 5');What happens if we execute the following query in both Sql Server and PostgreSQL?
select id,
category,
string_agg(product, ';')
over (partition by category order by id
rows between unbounded preceding and unbounded following) as stragg
from t1; See possible answers