Prashanth Jayaram

Technology enthusiast with 7+ years of experience in Database Technology. I am Microsoft Certified Professional with certificates of OCA, MCP, MCTS, MCITP developer, MCITP administration and backed with a degree in Master of Computer Application. My expertise lies in T-SQL programming, Replication, PowerShell and Performance Tuning. Hobbies are Drawing, playing soccer and listening to Melodies songs.

Blog Post

SQL to generate Asset Information – Configuration Manager SCCM 2012

SELECT   DISTINCT  s.Netbios_Name0 AS ComputerName,  
            s.Operating_System_Name_and0 AS OSName,  
            pr.Name0 AS ProcessorTypeSpeed,  
            pr.Manufacturer0 Manufacturer, 
            pr.NumberOfCores0 Cores, 
            pr.NumberOfLogicalProcessors0 LgicalProcessorCount, 
            case when pr.DataWidth0=64 then '64 bit'else'32 bit' end DataWidth, 
            m.TotalPhysicalMemory0/1024.00 AS MemoryMB,  
            GS1.TotalVirtualMemorySize0 VirtualMemory, 
            GS1.TotalVisibleMemorySize0 VisibleMemory, 
            ip.IPAddress0,  
            T1.COL AS TotalDriveSize, 
            LastBootUpTime0, 
            DATEDIFF(Day,GS1.LastBootUpTime0, GETDATE()) AS [Days since last boot]           
FROM v_R_System_Valid s  
       INNER JOIN v_GS_PROCESSOR pr ON s.ResourceID = pr.ResourceID 
       INNER JOIN v_GS_COMPUTER_SYSTEM gs ON s.ResourceID = gs.ResourceID  
       INNER JOIN v_GS_NETWORK_ADAPTER ON s.ResourceID = v_GS_NETWORK_ADAPTER.ResourceID  
       INNER JOIN v_GS_X86_PC_MEMORY m ON s.ResourceID = m.ResourceID 
       INNER JOIN v_GS_NETWORK_ADAPTER_CONFIGURATION ip ON s.ResourceID = ip.ResourceID 
      -- INNER JOIN v_GS_LOGICAL_DISK AS ld ON s.ResourceID = ld.ResourceID  
       INNER JOIN  
       ( SELECT RESOURCENAME,  
       col 
FROM  
(  
        SELECT DISTINCT TAB.Netbios_Name0 RESOURCENAME,  
            (  
            SELECT COL.deviceid0 +' '+ cast(COL.Size0/1024.00 AS varchar(20))+' ' 
            FROM v_GS_LOGICAL_DISK COL   
            WHERE   
                COL.ResourceID = TAB.ResourceID AND COL.DriveType0=3 
             FOR XML PATH ('')  
            ) COL  
FROM v_R_System_Valid TAB  
 )T  
 where T.COL is NOT NULL  
 ) T1 on T1.RESOURCENAME=s.Netbios_Name0 
       INNER JOIN V_GS_OPERATING_SYSTEM GS1 on GS1.ResourceID=s.ResourceID 
WHERE  
            s.Operating_System_Name_and0 LIKE '%Windows NT Server%' 
     AND  
       ip.IPAddress0 IS NOT NULL AND ip.DefaultIPGateway0 IS NOT NULL        

2015-12-11

649 reads

Blogs

AI: Blog a Day – Day 4: Transformers – Encoder, Decoder, and Attention

By

Continuing from Day 3 where we covered LLM models open/closed and their parameters, Today...

Flyway Tips: Multiple Projects

By

One of the nice things about Flyway Desktop is that it helps you manage...

What DevOps Look Like in Microsoft Fabric

By

Microsoft Fabric (not to be confused with the more general term “fabric” in DevOps)...

Read the latest Blogs

Forums

Can an Azure App Service Managed Identity be used for SQL Login?

By jasona.work

I'm fairly certain I know the answer to this from digging into it yesterday,...

Azure Synapse database refresh

By Sreevathsa Mandli

Hi Team, I am trying to refresh the Azure Synapse Dedicated pool from production...

how to write this query?

By water490

hi everyone I am not sure how to write the query that will produce...

Visit the forum

Question of the Day

Fun with JSON I

I have some data in a table:

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT *
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t;

See possible answers