2021-03-25
1,021 reads
2021-03-25
1,021 reads
2009-02-02
4,549 reads
Here is another "deleting duplicate records" script, this time in-place, using a uniqueidentifier column.
2009-01-15 (first published: 2008-12-30)
1,926 reads
If you attach a DB on an SQL Server different from the SQL Server where the DB was initially created, you will usually come up with a situation where a login will be a DB user however, you cannot see this through the login properties screen. That happens because the name of the login exists […]
2005-04-21 (first published: 2005-04-02)
1,410 reads
The usual practice, when we need some test data, is to employ the pseudo-random built-in function RAND(). We usually use it to produce a random value in some range and it produces these values with the same probabilities. Sometimes we need more "realistic" data when some values are more probable than others are. In this […]
2002-10-04
272 reads
This store procedure outputs the tables' usage figures in a usable (I hope) format. If you create in the master database it will show the information for the database that it runs against.
2002-04-11
385 reads
The script calculates the end and the beginning of the last, the current and the next months.
2002-04-01
987 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers