Grant Fritchey

Grant Fritchey is a SQL Server MVP with over 20 years’ experience in IT including time spent in support and development. Grant has worked with SQL Server since version 6.0 back in 1995. He has developed in VB, VB.Net, C# and Java. Grant has authored books for Apress and Simple-Talk, and joined Red Gate as a Product Advocate in January 2011. Find Grant on Twitter @GFritchey or on his blog as the Scary DBA.

SQLServerCentral Editorial

Information Security, ITs Abused Step Child

Many of us grew up with one version of Cinderella or another. The step child that's horribly mistreated by the new parent is a scary story. In the Disney version, everything works out fine. However, if you read some of the original Grimm versions of the story (and there is more than one version), not […]

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2021-01-30

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Blog Post

The Learning Curve for DevOps

If you’re attempting to implement automation in and around your deployments, you’re going to find there is quite a steep learning curve for DevOps and DevOps-style implementations. Since adopting...

2020-11-25 (first published: )

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Blogs

The Book of Redgate: Profits

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Redgate is a for-profit company. We look to make money by building and selling...

Session Materials for Techorama & DataGrillen 2026

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I’ve uploaded the slides for my Techorama session Microsoft Fabric for Dummies and my...

Stop Using Pandas for Aggregations — Try DuckDB Instead

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If you've ever loaded a 2 GB CSV into pandas just to run a...

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Forums

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The New Software Team

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Database Mail in SQL Server 2022

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Question of the Day

The string_agg function

We create the following table and then insert some records in it:

create table t1 (
   id int primary key,
   category char(1) not null,
   product varchar(50)
);

insert into t1 values
(1, 'A', 'Product 1'),
(2, 'A', 'Product 2'),
(3, 'A', 'Product 3'),
(4, 'B', 'Product 4'),
(5, 'B', 'Product 5');
What happens if we execute the following query in both Sql Server and PostgreSQL?
select id, 
category, 
string_agg(product, ';')
                 over (partition by category order by id
                 rows between unbounded preceding and unbounded following) as stragg
from t1;

See possible answers