SQL Table Columns Disappear in Access
A couple weeks ago a user complained that on one of our development databases, one of the views he was...
2011-09-28
1,624 reads
A couple weeks ago a user complained that on one of our development databases, one of the views he was...
2011-09-28
1,624 reads
Because this was a problem that Google was zero help on and I did find a couple other people afflicted...
2011-09-21
2,186 reads
This is a technique I’m sure many people are already using in their environments. Instead of using the actual name...
2011-09-14
3,607 reads
Here are a couple more SSMS tricks I’ve stumbled upon recently. Both involve the functionality of registered servers. If you...
2011-04-17
1,611 reads
This is one that I figured most everyone would know, but repeatedly over the past couple weeks in my office,...
2011-04-02
1,361 reads
Most of us like things that make our lives easier. When they’re free, it’s just that much sweeter. I would...
2011-02-13
1,582 reads
This isn’t exactly the best thing since bread (or even sliced bread for that matter), but I figured I’d share...
2011-02-07
1,317 reads
So… this is late. And I missed my q3 goals review all together. Oh well, not much I can do...
2011-01-23
731 reads
Last year I posted professional goals along with quite a few other bloggers and it helped to keep me somewhat...
2011-01-23
769 reads
So, after a rather hectic few months, I’m finally crawling back out of the hole I’ve been occupying and getting...
2010-09-16
745 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
Many years ago, before I joined Oracle, I was working on a major modernisation...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers