Work time calculation
One way to calculate how many minutes a person has worked considering holidays and shifts, being given starting and ending date / time
2016-09-29 (first published: 2016-09-08)
571 reads
One way to calculate how many minutes a person has worked considering holidays and shifts, being given starting and ending date / time
2016-09-29 (first published: 2016-09-08)
571 reads
Foreign Keys are one of the fundamental characteristics of relational databases and enforce the referential integrity. Is it a good idea to index a FK relationship? When can it help?
2016-09-16 (first published: 2015-06-29)
15,729 reads
SQL Server 2014 has introduced a rebuilt Cardinality Estimator (CE) with new algorithms. Which are the biggest differences between the new CE and the previous one? Which one works better? Read more to find out.
2015-04-09
6,798 reads
By Steve Jones
This value is something that I still hear today: our best work is done...
By gbargsley
Have you ever received the dreaded error from SQL Server that the TempDB log...
By Chris Yates
Artificial intelligence is no longer a distant concept. It is here, embedded in the...
Hi everyone I am writing an SP where there is logic inside the SP...
Comments posted to this topic are about the item Planning for tomorrow, today -...
We have a BI-application that connects to input tables on a SQL Server 2022...
I try to run this code on SQL Server 2022. All the objects exist in the database.
CREATE OR ALTER VIEW OrderShipping AS SELECT cl.CityNameID, cl.CityName, o.OrderID, o.Customer, o.OrderDate, o.CustomerID, o.cityId FROM dbo.CityList AS cl INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID GO CREATE OR ALTER FUNCTION GetShipCityForOrder ( @OrderID INT ) RETURNS VARCHAR(50) WITH SCHEMABINDING AS BEGIN DECLARE @city VARCHAR(50); SELECT @city = os.CityName FROM dbo.OrderShipping AS os WHERE os.OrderID = @OrderID; RETURN @city; END; goWhat is the result? See possible answers