Now that everyone else said it – I’m an MVP!
They say to save the best for last and while I’m not so sure about that I was truly honored...
2011-01-29
474 reads
They say to save the best for last and while I’m not so sure about that I was truly honored...
2011-01-29
474 reads
SQL Stadium will be crowded with anticipation very soon in Tampa. Come watch as Adam Jorgensen takes on a challenger...
2010-12-20
869 reads
This season, as we continue to grow and partner with some of the best of the best in the industry....
2010-12-15
506 reads
Have you been trying to figure out how to take your career in Microsoft BI, SharePoint and SQL Server to...
2010-12-10
496 reads
Have you ever been “dragged” to a long weekend afternoon at a craft fair? Did it look something like this?
This...
2010-12-02
472 reads
Hey folks, we all know that there are some great training organizations out there (AHEM Pragmatic Works, AHEM). I hate...
2010-11-22
410 reads
Hey folks – It’s time again for SQL Saturday Tampa. Original Birthplace of Iron Chef SQL Server. I have submitted this...
2010-11-22
583 reads
Hey folks – A quick one today since I’m travelling, but I am sharing something I often share with my clients...
2010-11-22
529 reads
Hey folks, Just a quick preview that we’re hard at work again on a new book with Wiley publishing focused...
2010-11-22
419 reads
Today is a topic that is close to my heart. Many of you probably don’t know that the SQL pass...
2010-11-22
534 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers