Sitting in Judgment
I have been meaning to write this for a while, but i wanted to wait for a break in SQLDrama....
2010-10-26
362 reads
I have been meaning to write this for a while, but i wanted to wait for a break in SQLDrama....
2010-10-26
362 reads
Ok so I know this is late, but I wanted to thank Jack, Andy and the team at the Orlando...
2010-10-26
343 reads
For those of you who have seen our team present, we always do our best to make it really informative,...
2010-10-26
860 reads
Thanks for coming to today's webinar. We had a great turnout and hope to see you again soon. I have...
2010-09-28
437 reads
Hey there folks. I am so excited about the tremendous turnout at the 24 hours of PASS. There were so many...
2010-09-17
353 reads
With so many folks out there struggling and loking for new opportunities you may want to take some time away...
2010-09-16
328 reads
I thought I would pass along something I learned this week about batches in TSQL. I always knew about the...
2010-09-16
373 reads
Many of you have been wondering where I will be speaking next. So I apologize for not replying to you...
2010-09-16
486 reads
Hey folks,
The 24 hours of PASS is coming very quickly.http://www.sqlpass.org/24hours/fall2010/. There are so many great sessions that I don’t know...
2010-09-06
505 reads
Motivational time again!
Have you ever worked on a project where someone was seeking their moment in the sun for an...
2010-09-06
213 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers