SSAS Maestro - Redmond Recap
Well today was the last day for a while I would be greeted by this sign:
It was a pretty exciting...
2011-06-18
842 reads
Well today was the last day for a while I would be greeted by this sign:
It was a pretty exciting...
2011-06-18
842 reads
Wow, what a day 2! This was our first day of lecture and it was a doozy. Stacia and I...
2011-06-14
857 reads
Well it’s been an exciting couple of weeks leading up to this course. We have tweaked what we could in...
2011-06-13
627 reads
One of the things I’m most proud of at our company is our team.You can see some of our team...
2011-02-11
701 reads
This next week I’m launching a series of posts centered around how you could be a part of the leading...
2011-02-10
614 reads
Ok so dynasty might be a bit strong, but check out this
newest volume from the folks @ Pragmatic Works. We...
2011-02-08
619 reads
And a bunch of other people who are really talented. My Zero to Cube session won the Summit Spotlight track...
2011-02-08
751 reads
Hey folks. I think we can all agree that there is some really quality training available for free on the...
2011-01-30
1,429 reads
Let me start of by saying I could have taken this picture in Florida. But I didn’t. I was in...
2011-01-30
1,313 reads
Hey Everyone – SQL Rally Voting opens today for the BI Track. There are lots of good sessions and at the...
2011-01-30
1,325 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers