Although, generally speaking, source control is the truth, a database doesn't quite conform to the ideal because the target schema can, for valid reasons, contain other conflicting truths that can't easily be captured in source control. Dave Ballantyne explains the problems and suggests a solution.
2012-09-03
1,904 reads
Sept 15th, 2012 at the CAIT Campus of Washington University in St.Louis - 5 Jackson Avenue, Clayton, MO 63105
SQL Saturday #154 is the very first SQL Saturday event in the St.Louis area. It is a free one day event for SQL Server professionals and those wanting to learn about SQL Server. We are planning on a 4 track event with 200 attendees. We currently have several sessions aligned towards Database Administration, Application Development, Business Intelligence and professional Development Tracks. We also have several sessions focused on SQL Server 2012! Please visit our event website for more details and free registration.
2012-09-03 (first published: 2012-08-06)
2,153 reads
Come visit Rhode Island and meet fellow SQL Server professionals from all over New England as SQL Saturday comes on Sept 15, 2012.
2012-09-03 (first published: 2012-08-13)
1,762 reads
Why does the transaction log fill up? There are a variety of reasons, and MVP Gail Shaw walks you through the various things to check.
2012-08-31 (first published: 2011-02-21)
63,995 reads
SQL Server 2012 AlwaysOn Availability Groups provides a unified high availability and disaster recovery (HADR) solution that improves upon legacy functionality previously found across disparate features. Prior to SQL Server 2012, several customers used database mirroring to provide local high availability within a data center, and log shipping for disaster recovery across a remote data center. With SQL Server 2012, this common design pattern can be replaced with an architecture that uses availability groups for both high availability and disaster recovery. This paper details the key topology requirements of this specific design pattern, including quorum configuration considerations, steps required to build the environment, and a workflow that shows how to handle a disaster recovery event in the new topology.
2012-08-31
2,399 reads
I need to try and find all SQL Servers, not just the ones in my domain. We know there are a couple of appliances that are potentially running SQL Server and we want to see them, too. What can I use to do this?
2012-08-30
2,882 reads
There are seven common antipatterns in T-SQL coding that make code perform badly, and three good habits which will generally ensure that your code runs fast. If you learn nothing else from this list of great advice from Grant, just keep in mind that you should 'write for the optimizer'.
2012-08-29
7,758 reads
This article discusses and demonstrates AlwaysOn Availability groups in SQL Server 2012, a new feature for high availability.
2012-08-28
9,980 reads
Can I export images from SQL Server to a file in Windows? What SQL Server options are available to do so? Check out this tip to learn more.
2012-08-28
3,504 reads
A free day of training in Columbus, GA. Come meet the local SQL professionals and spend a day talking SQL Server.
2012-08-28 (first published: 2012-08-09)
2,187 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
Comments posted to this topic are about the item Split Large Queries in Athena...
Comments posted to this topic are about the item Finding Trailing Spaces
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers