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SQL Server Luxembourg User Group

Come join the SQL Server Luxembourg UG for free training and networking on June 27th at 5:30pm. Soren Nielsen will take a Deep Dive into SQL Server 2012’s “Always On” High Availability technology. This will be followed by Vern Rabe of the SQL User Group in Portland, Oregon, presenting “Data Types - Think You Know It All? Think Again”.

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2013-06-25

2,225 reads

Technical Article

The Switch Workshop, by Red Gate and Re-Wired Group

Customers don’t just buy a product — they switch from something else. And customers don’t just leave a product — they switch to something else. It’s in these switching moments that the deepest customer insights can be found. On the 25th of July, a select group of 32 people will attend a unique, hands-on, full-day workshop at Red Gate to learn about “The Switch”.

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2013-06-24

1,838 reads

Technical Article

Maximizing Throughput with TVPs

TVPs offer several performance optimization possibilities that other bulk operations do not allow, and these operations may allow for TVP performance to exceed other bulk operations by an order of magnitude, especially for a pattern where subsets of the data are frequently updated.

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2013-06-21

4,644 reads

Technical Article

SQL Saturday #226 - South Florida

SQLSaturday is a training event for SQL Server professionals and those wanting to learn about SQL Server. This event will be held Jun 29 2013 in Davie, FL. Admittance to this event is free, all costs are covered by donations and sponsorships. Please register soon as seating is limited, and let friends and colleages know about the event.

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2013-06-21

1,808 reads

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Question of the Day

Adding new column with DEFAULT

Which number will the COUNT() return after executing the following statements:

DROP TABLE IF EXISTS #test;
CREATE TABLE #test (id INT)
INSERT INTO #test (id)
SELECT *
  FROM GENERATE_SERIES(1, 3) AS gs
;

ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0;
go
UPDATE #test SET flag = 0 WHERE id = 1
UPDATE #test SET flag = 1 WHERE id = 2

INSERT INTO #test (id) VALUES (4)

SELECT COUNT(*)
  FROM #test AS t
 WHERE flag = 0
 

See possible answers