2013-09-17 (first published: 2013-02-08)
662 reads
2013-09-17 (first published: 2013-02-08)
662 reads
2013-09-17 (first published: 2013-09-06)
1,447 reads
2013-09-12 (first published: 2013-02-08)
1,877 reads
Use this script to find all the Foriegn Keys and their details in a database
2013-09-11 (first published: 2013-09-02)
1,419 reads
Script queries backupset & backupmediafamily tables to get latest backup file, then generates script to restore db using backup file and moves files to new locations.
2013-09-10 (first published: 2013-08-28)
1,344 reads
Kill any user processes per database or for the entire server instance.
2013-09-05 (first published: 2013-08-21)
1,515 reads
Found this lovely T-SQL script to display the SELECT statement for any table.
2013-08-22 (first published: 2013-08-06)
3,232 reads
This script shows size information of every database on the instance.
2013-08-21 (first published: 2010-07-26)
5,938 reads
Create views based on table definitions for backwards compatibility when relocating tables to a new database.
2013-08-16 (first published: 2013-07-30)
1,108 reads
Transact-SQL does not have a simple method to launch multiple parallel running scripts. This tool will change the game. It requires SQL Server 2005 or above.
2013-08-13 (first published: 2009-08-28)
17,463 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers