Display COUNT(*) but ONLY TOP 100
Let’s say you have a result set with 5000 records but you want to display only 100 of them and in the same time to display the count of ALL records (5000).
2009-11-20 (first published: 2009-11-05)
2,465 reads
Let’s say you have a result set with 5000 records but you want to display only 100 of them and in the same time to display the count of ALL records (5000).
2009-11-20 (first published: 2009-11-05)
2,465 reads
Split string like ('123,43,5465,6788,1231,111', ',') into table, separator (,) can be more than 1 char
2009-11-19 (first published: 2009-11-05)
1,377 reads
Data compression is a key feature with SQL 2008. This script, can compress all DB objects (partition/non-partitioned) according to Partition Range you specifiy.
2009-11-18 (first published: 2009-11-05)
1,158 reads
2009-11-17 (first published: 2009-11-06)
1,007 reads
This procedure searches for your criteria not only in code, but also in objectnames
2009-11-16 (first published: 2009-10-20)
1,091 reads
Returns records with errors from the default trace ordered by most recent first
2009-11-12 (first published: 2009-10-29)
703 reads
This procedure checks if a mirror treshold exists and wait until this treshold is cleared or after a specified time.
2009-11-10 (first published: 2009-10-23)
500 reads
A useful SQL function to parse a single string with delimited values for the "N"th occurrence
2009-11-06 (first published: 2009-10-15)
1,443 reads
There are times when maintenance plan is too simple to do the job, and SSIS is unreachable for you. Here is a simple stored procedure to help you.
2009-11-05 (first published: 2009-10-09)
1,551 reads
Retrieve consecutive records from the table based the value difference
2009-11-04 (first published: 2009-10-06)
951 reads
By Brian Kelley
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Comments posted to this topic are about the item Why SQL Server Database Attach...
Comments posted to this topic are about the item Fixing P1 Queries
Comments posted to this topic are about the item BIT_COUNT() IV
In SQL Server 2025, I run this code:
select bit_count('A')
What is returned? See possible answers